Question

12. The total events to throw three dice simultaneously is
(a) 6
(b) 18
(c) 81
(d) 216
1

Answer 1

Answer:

ȶɦʀɛɛ ɖɨʄʄɛʀɛռȶ ɖɨƈɛ ǟʀɛ ȶɦʀօառ ǟȶ ȶɦɛ ֆǟʍɛ ȶɨʍɛ. ȶɦɛʀɛʄօʀɛ, ȶօȶǟʟ ռʊʍɮɛʀ օʄ քօֆֆɨɮʟɛ օʊȶƈօʍɛֆ աɨʟʟ ɮɛ 63 = (6 × 6 × 6) = 216.

Answer 2

Answer:

d

Step-by-step explanation:

Total no of events =6^n

Here n=3

6^3=216