Question

12 The unit of permiability of free space is a) T.m/A b) T.m^2/A c) T.m/A^2 d) None of these ​

Answer 1

Answer:

Correct option is

C

Wbm  

−1

A  

−1

 

We know that B=  

4π

μ  

0

​  

 

​  

 

r  

2

 

Idlsin(θ)

​  

 

Now by putting SI units of all measurable quantities in above formula⇒  

m  

2

 

Wb

​  

=  

m  

2

 

xAm

​  

 

(where x is the assumed SI unit of μ  

0

​  

)

⇒x=  

A.m

Wb

​  

 

Explanation:

Answer 2

thanks for Ur points....