Question

12.The Zeroes of the Polynomial x2 -2x -8 are –

Answer 1

$\bf\huge\green{\underbrace{ ★ Solution : }}$

★ Given polynomial,

↪ p(x) = x² - 2x - 8 = 0

★ Let,

• a = 1
• b = - 2
• c = - 8

$\sf\:⟹ Sum \: of \: the \: zeroes : \alpha + \beta = \frac{- b}{a} = \frac{-(-2)}{1}= 2$

$\sf\:⟹ Product \: of \: the \: zeroes : \alpha \beta = \frac{c}{a} = \frac{-(-8)}{1}= 8$

# Hence, it is solved...

Answer 2

Answer

x=4 or x=-2

Step by step explaniation:

• Give polynomial p(x) = x2 - 2x-8
• take p(x) = 0