Question

12. There are three consecutive integers such that the square of the first increased by
4.52
MATHEMATE
QUADRA
product of the other two gives 154. What are the integers?
multiples of 5 is 300. Determine them
38. The​

Answer 1

Question:-

There are three consecutive integers such that the square of the first increased by the product of the other two gives 154.what are the integers?

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The three consecutive integers are 8,9,10.

Given:

There are three consecutive integers such that the square of the first increased by the product of the other two gives 154.what are the integers?

Solution:-

Let the numbers be x, x+1, x+2

It is given that,

x² + (x + 1) (x + 2) = 154

x² + x²+ 2x + x +2 = 154

2x² + 3x - 152 = 0

2x² - 16x + 19x -152 = 0

2x (x-8) + 19 (x-8) = 0

On simplification,

we get,

x = 8

Therefore, the next two consecutive terms are

X+1 = 9, x + 2 = 10

The numbers are 8, 9, 10.

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Answer 2

Answer:

12. There are three consecutive integers such that the square of the first increased by

4.52

MATHEMATE

QUADRA

product of the other two gives 154. What are the integers?

multiples of 5 is 300. Determine them

38. The