Question

12. There is a 2.5 meter wide path around the square shaped garden of Shiraj's. The area of
path is 165 sq meter. Let us calculate the area of garden and the length of diagonal,​

Answer 1

Answer:

Length of the garden

= L - 2 × width of path

= L – 2(2.5) = (L – 5)

Breadth of the garden

= B - 2 × width of path

= B – 5

We know, area of square = length × breadth

Area of the garden = (L - 5)(B - 5)

Total Area = L × B

Area of path = Total Area – Area of garden = 165

LB - (L - 5)(B - 5) = 165

⇒ LB – LB + 5L + 5B - 25

⇒ 5B + 5L - 25 = 165

⇒ 5(L + B) = 190

⇒ L + B = 38m

Let L = 20m

B = 18m

Area of the garden = (20 - 5)(18 - 5) = 195m2

We know, diagonal of a rectangle

Where, L = length of rectangle and B = breadth of rectangle

Length of the Diagonal =

= 27m