*12
Therefore smaller number x 12 and
Bigger number = x+ 5 = 12 + 5 = 17
Example 4. The length of a rectangle shaped park exceeds its breadth by 17
meters. If the perimeter of the park is 178 meters, then find the dimensions of the
park?
Solution: Let the breadth of the park be = x meters
Then the length of the park - x + 17 meters
.. perimeter of the park 2 (longth + breadth)
2(x + 17 + x) moters
2 (2x + 17) meters
But it is given that the perimeter of the rectangle is 178 meters
2 (2x +17) – 178
4x + 34 - 178
4x178 34
PER
36
Therefore, breadth of the park = 36 meters
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answer in the picture ok..
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