Question

12. Three consecutive integers are such that
when they are taken in increasing order
and multiplied by 2. 3 and 4 respectively.
they add up to 56. Find these numbers.​

Answer 1

Answer:

5,6,7

Step-by-step explanation:

Let us assume the first integer as X, as you have said consecutive integers, the three integers would be X, (X+1), (X+2)

As per question, X*2+(X+1)*3+(X+2)*4= 56

2X+3X+3+4X+8= 56

9X= 56-8-3

X= 45/9

X=5

First integer is 5

Second is 5+1=6

Third is 5+2=7