Question

12. Three resistances of 2,3 and 5 ohms are connected in series. If the combination is connected to a battery of 4 volts then what will be :
a. Current in each resistance
b. Potential difference across each resistance.​

Answer 1

Answer:

i will tell u one thing but...

Answer 2

R eff=2+3+5=10 ohm
V=4V
I=?
V=IR(ohms law)
4V=I*10 OHM
I=0.4A
CURRENT IN EACH RESISTANCE IS 0.4 AMP. (CURRENT IN SERIES REMAINS SAME FOR ALL RESISTORS)

V across 2 ohm resistor :
R=2 ohm
I=0.4
V=IR( Ohms law)
V=0.4*2
=0.8 V


V across 3 ohm resistor:
R=3 ohm
I=0.4 A
V=IR(ohms law)
V=0.4*3
=1.2 V


V across 5 ohm resistor:
R=5ohm
I=0.4A
V=IR (ohms law)
V=0.4*5
= 2 A




Hope it helps