12. Two cross roads, each of width 5 m, run at right angles through the centre of a
rectangular park of length 70 m and breadth 45 m and parallel to its sides. Find
the area of the roads. Also find the cost of constructing the roads at the rate of
105 per m2
Answers
Given :-
• The width of each road is 5 m
• The length and breath of a rectangular park is 70m and 45 m and parallel to its sides.
• The cost of constructing the road at per m^2. = 105 m
Solution :-
Width of the road = 5 m
According to the question,
Length of first parallel road = 70 m
[ Opposite sides of || are equal ]
Therefore,
The Area of first road = 5 * 70 = 350 sq.m
Now,
The Length of the second road = 45 m
Therefore,
Area of second road = 45 * 5 = 225 sq. m
Area of the common part of the cross roads with 5 m width that lies at the centre of the park
= 5 * 5 = 25
Now,
Total Area of roads = Area of first road + Area of second road - common area
Put the required values,
= 350 + 225 - 25
= 575 - 25
= 550 sq. m
Now
Cost of construction Per. sq m = Rs 105
Therefore,
Total Cost of constructing
= 550 * 105= Rs 57750
Step-by-step explanation:
⭐️Question ::-
Two cross roads, each of width 5 m, run at right angles through the centre of a
rectangular park of length 70 m and breadth 45 m and parallel to its sides. Find
the area of the roads. Also find the cost of constructing the roads at the rate of
105 per m^2
⭐️Given ::-
• The width of each road is 5 m
• The length and breath of a rectangular park is 70m and 45 m and parallel to its sides.
• The cost of constructing the road at per m^2. = 105 m
⭐️Required Solution ::-
Width of the road = 5 m
According to the question,
Length of first parallel road = 70 m
[ Opposite sides of || are equal ]
Therefore,
The Area of first road = 5 * 70 = 350 sq.m
Now,
The Length of the second road = 45 m
Therefore,
Area of second road = 45 × 5 = 225 sq. m
Area of the common part of the cross roads with 5 m width that lies at the centre of the park
= 5 × 5 = 25
Now,
Total Area of roads = Area of first road + Area of second road - common area
Put the required values,
= 350 + 225 - 25
= 575 - 25
➡ 550 sq. m
Now
Cost of construction Per. sq m = Rs 105
Therefore,
Total Cost of constructing
= 550 × 105
➡ Rs 57750..
Hope it helpful.. ✌️