12: Two dice are thrown. Let A be the event that the sum of the
points on the faces is 9.let B be the event that at least one
number 6.Find P(AUB)=
Answers
Answer:
Step-by-step explanation:
Ok
Given : Two dice are thrown.
A be the event that the sum of the points on the faces is 9.
B be the event that at least one number 6.
To Find : P(AUB)
Solution:
Two dice are thrown.
hence possible outcomes = 6 * 6 = 36
P(AUB) = P(A) + P (B) - P ( A∩B)
A = sum of the points on the faces is 9.
=> A = { ( 3 , 6) , ( 4 , 5) , ( 5 , 4 ) , ( 6 , 3) }
=> n(A) = 4
B = at least one number 6.
=> B = { (1 , 6) , ( 2 ,6 ) , ( 3 , 6) , ( 4 , 6) , ( 5 , 6) , ( 6 , 6) , ( 6 , 5) , ( 6 , 4) , ( 6 ,3 ) , ( 6 ,2 ) , ( 6 , 1) }
n(B) = 11
A∩B means sum of the points on the faces is 9. and at least one number 6.
=> A∩B = { ( 3 , 6) , ( 6 , 3) }
n ( A∩B) = 2
n (AUB) = 4 + 11 - 2 = 13
P(AUB)= = 13/36
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