12. Two different dices are tossed together. Find the probability of
i) getting an even number on each die
ii)getting a doublet.
Answers
Given:-
- Two different dices are tossed together.
To Find:-
- Find the probability of
i) getting even number on each die
ii)getting a doublet.
Solution:-
Probability of an event P(E) = Number of outcomes/Total Number of outcomes
(i) P(getting an even number on each die)
= 9/36 = 1/4
(ii) P(getting a doublet)
= 6/36 = 1/6
When two dice are tossed together,
Total possible outcomes
=
6 2
36
.
(i)P(doublet) :
The favorable outcomes
=
{(1,1),(2,2),(3,3),(4,4),(5,5),(6,6)}
Number of favorable outcomes
=
6
∴ Probability of getting a doublet
=
P(doublet)=
36
6
=
6
1
.
(ii)P(sum= 10) :
The favourable outcomes
=
{(4,6),(5,5),(6,4)}
Number of favorable outcomes
=
3
∴ Probability of getting a sum 10
=
P(sum=
10)=
36
3
=
12
Answer:
Two different dice are tossed together. Find the probability:
(i) of getting a doublet
(ii) of getting a sum 10, of the numbers on the two dice.
The outcomes when two dice are thrown together are
(1,1), (1,2), (1,3), (1,4), (1,5), (1,6)
(2,1), (2,2), (2,3), (2,4), (2,5), (2,6)
(3,1), (3,2), (3,3), (3,4), (3,5), (3,6)
(4,1), (4,2), (4,3), (4,4), (4,5), (4,6)
(5,1), (5,2), (5,3), (5,4), (5,5), (5,6)
(6,1), (6,2), (6,3), (6,4), (6,5), (6,6)
Total number of outcomes = 36
n (s) = 36
i) A = getting a doublet
A = {(1,1), (2,2), (3,3),(4,4), (5,5), (6,6)}
n(A) = 6
B = getting sum of numbers as 10.
B = {(6, 4), (4, 6), (5, 5)}
n(B) =3
Step-by-step explanation:
Hi Bunny !!
I gave 2 answers !!
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