Question

12. Two equal and opposite forces Feach are applied
along a rod of transverse sectional area A.
The normal stress to a section PQ inclined o to
transverse section is
Froso
Tea
>
F
Fsine
(1)
(2) – cose
DIT DITT
(3) Esin 2e
Ecos e​

Answer 1

A force F is being applied along a rod of transverse sectional area A,

Let the Force be = F

Let the Area be = A

The normal stress is given as pcosФ, where p is the pressure

Therefore,

p = F/A

Hence,

Normal stress = F/A × cosФ

Thus, the normal stress to a section PQ inclined o to  transverse section is  F/AcosФ