Question

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12. Two equal chords PQ and RS of a circle intersect at A. A is
joined to O, the centre of the circle. Prove that OA bisects angle PAS​

Answer 1

Answer:

draw 2 imaginary lines PO and OS

then write :-

In triangle PAO and OAS

PO = OS ( radius of a circle )

OA = AO ( common )

angle POA = angle SOA ( both 90° )

triangle PAO is congruent to triangle OAS ( RHS congruency rule )

therefore, angle PAO = angle SAO. ( CPCT )

therefore, OA bisects angle PAS

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Answer 2

Answer:

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