Physics, asked by Lakshithkumar, 11 months ago

12. Two kittens are on opposite sides of a field, 250 m apart. Kitten A runs at a
constant speed of 25 m/s due east on a collision course with kitten B, which is
traveling west at 12 m/s. How much time elapses before the two kittens
collide?​

Answers

Answered by santy2
32

Answer:

Two kittens are on opposite sides of a field, 250 m apart. Kitten A runs at a

constant speed of 25 m/s due east on a collision course with kitten B, which is traveling west at 12 m/s. How much time elapses before the two kittens to collide?

It takes about 6.76 seconds for the kittens to collide

Explanation:

This is a question of relative speed:

The relative speed for the two kittens is:

25 m/s + 12 m/s = 37 m/s

There the two kittens together cover a distance of 37 m every second moving towards each other.

Calculate the time they meet

Meeting time = Relative speed/ total distance to be covered

Time of meeting = 250 m / 37m/s

= 6.76 seconds

Therefore it takes 6.76 seconds for the two kittens to collide.

Answered by destructionboys996
0

Answer:

t=6.76s

Explanation:

Firstly calculate your relative speed between Kitten A and Kitten B where we take east as being positive and west as being negative



V= V^east -V^west
V=25m/s -(-12m/s)
V=25m/s +12m/s
V=37m/s east


Then from our question above we know that our displacement is 250m

X=Vt
250m=(37m/s)t
t=250m / 37m/s
t=6.756756757s

so we going to round off the answer to two decimal places which will be t=6.76 s

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