Question

12. Two lines AB and CD intersect each other at a point O such that angle AOC: angle AOD = 5:7. Find all the angles. ​

Answer 1

Let ∠AOC = 5k and ∠AOD = 7k, where k is some constant.

Here, ∠AOC and ∠AOD form a linear pair.

∴ ∠AOC + ∠AOD = 180º

⇒ 5k + 7k = 180º

⇒ 12k = 180º

⇒ k = 15º

∴ ∠AOC = 5k = 5 × 15º = 75º

∠AOD = 7k = 7 × 15º = 105º

Now, ∠BOD = ∠AOC = 75º (Vertically opposite angles)

∠BOC = ∠AOD = 105º (Vertically opposite angles)

Answer 2

Answer:

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