Question

12. Two men are on opposite sides of a tower. They measure the angles of elevation of the top of the tower as 30° and 45° respectively. If the height of the tower is 50 metres, find the distance between the two men.
[Take √3 = 1.732.]​

Answer 1

Step-by-step explanation:

135.5m

Correct Answer:

A) 136.6m

Let height of tower = BD

Distance b/w both person = AC

1 unit = 50 m

AC=(1+

√

3

) unit=50(1+

√

3

)

=50+50

√

3

=50+50×1.732

=50+86.6=136.6m