12. Two resistors are connected in series gives an
equivalent resistance of 10 2. When connected
in parallel, gives 2.4 2. Then the individual
resistance are
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Answer:
Step-by-step explanation:
R + R `= 102
1/R +1/ R` =1/2.42
(R`+R)/RR`= 100/242
102/RR`=100/242
RR`=102*242/100
RR`= 246.84
R=246.85/R`
246.84/R` +R`=102
246.84+R²`=102R`
I hope
You can solve the rest on ur own ......
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