Question

12.
Two years ago, a father was 4 times as old as his son. After 8
yrs
his
age exeeds twice his sons age oy 10 yrs. The ratio o
ages after 3 yrs will be?​

Answer 1

Answer:

Let the present age of the father be:x

And that of the son be :y

Therefore from 1st condition:

(x-1)=4(y-1)

(x-1)=4y-4

x-4y=-4+1

x-4y=-3———————equation 1

From 2nd condition,

(x+6)=2(y+6)+9

x+6=2y+12+9

x-2y=15———————equation 2

Therefore after subtracting equation 1 from 2 we get,

y=9

Now let's replace y with 9 in 2nd equation,

We have,

x-18=15

x=33

Hence the present ages of father and his son are 33 and 9 respectively!!

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