12 V
1. Five resistances are connected in the shape of letter A as shown
in figure. Determine the total resistance of the circuit. Also find
the current in 792 resistance.
[Ans. 1592, 0.05A]
Answers
Answer:
12th
Physics
Current Electricity
Equivalent Resistance in Series-Parallel
The equivalent resistance b...
PHYSICS
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Asked on December 20, 2019 by
Gurpreet Pradhan
The equivalent resistance between A and B in the figure is:
174009
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ANSWER
In this case, the 2 resistors of 3 ohms and 2 ohms on the upper half of the circuit are connected in series and the combined resistance R1 is given as 3+2 = 5 ohms.
The 2 resistors of 6 ohms and 4 ohms on the lower half of the circuit are connected in series and the combined resistance R2 is given as 6+4 = 10 ohms.
The resistances R1, R2 and 30 ohms in the middle are connected in parallel. So the total resistance R of this parallel connection is given as
5
1
+
10
1
+
30
1
=
0.33
1
=3ohms. That is, the resistance in the closed loop is reduced to 3 ohms.
Hence, the value of the resistance in the circuit between A and B is 3 ohms.