Math, asked by pawan130477, 9 months ago

12. Value of the roots of the quadratic equation, x2 - x - 6 = 0 are​

Answers

Answered by sweett2314
2

Answer:

x=-2 x=3

Step-by-step explanation:

Factoring x2-x-6

The first term is, x2 its coefficient is 1 .

The middle term is, -x its coefficient is -1 .

The last term, "the constant", is -6

Step-1 : Multiply the coefficient of the first term by the constant 1 • -6 = -6

Step-2 : Find two factors of -6 whose sum equals the coefficient of the middle term, which is -1 .

-6 + 1 = -5

-3 + 2 = -1 That's it

Step-3 : Rewrite the polynomial splitting the middle term using the two factors found in step 2 above, -3 and 2

x2 - 3x + 2x - 6

Step-4 : Add up the first 2 terms, pulling out like factors :

x • (x-3)

Add up the last 2 terms, pulling out common factors :

2 • (x-3)

Step-5 : Add up the four terms of step 4 :

(x+2) • (x-3)

Which is the desired factorization

Equation at the end of step 1 :

(x + 2) • (x - 3) = 0

Answered by pratham280604
2

Answer:

x=-2,3

Step-by-step explanation:

x^2-x-6=0

x^2-3x+2x-6=0

x(x-3)+2(x-3)=0

(x+2)+(x-3)=0

x=-2,3

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