Question

12. varun is guessing which of the 2 hands holds a coin. What is the probability that varun guesses correctly 3times?

Answer 1

Answer:

1/8

Step-by-step explanation:

since , Varun has two hands , the probability of holding coins is 1 / 2

(i.e he may hold either in one hand or another hand ).

Then , Guess by varun for three times will be ,

= 1 / 2 * 1 / 2 * 1 / 2

= 1 / 8

Answer 2

Given,

Varun is holding a coin in one of his hands.

To find,

The probability that Varun guesses which of his 2 hands holds the coin, correctly for 3 times.

Solution,

We can simply solve this mathematical problem using the following process:

Mathematically,

The probability of occurrence of a favorable event = P (favorable event)

= (Total number of occurrence of the favorable event) / (Total number of occurrence of all possible events)

= (Total number of occurrence of the favorable event) / (Total number of trials)

As per the given question;

For each time Varun guesses which of his 2 hands holds the coin and guesses which of his hand has the coin;

Total trials = 2 {Since he will either guess the correct hand or else the wrong hand, hence only 2 possibilities in the event}

Number of favorable occurrences = 1 {Since the only one favorable occurrence is that Varun guesses the correct hand}

Now,

The probability that he guesses correctly each time

= (Total number of occurrence of the favorable

event) / (Total number of trials)

= 1/2

So,

The probability that Varun guesses which of his 2 hands holds the coin, correctly for 3times

= (The probability that he guesses correctly in the first time) x (The probability that he guesses correctly in the second time) x (The probability that he guesses correctly in the third time)

= 1/2 x 1/2 x 1/2

= 1/8

Hence, the probability that Varun guesses which of his 2 hands holds the coin, correctly for 3times, is equal to 1/8.