12. Verify: (ab + bc) (ab – bc) + (bc + ca) (bc – ca) + (ca + ab) (ca – ab) = 0
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Given,
L.H.S.=>(ab + bc) (ab – bc) + (bc + ca) (bc – ca) + (ca + ab) (ca – ab)
= (ab)²-(bc)²+(bc)²-(ca)²+(ca)²-(ab)²
=0
=R.H.S.
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