Question

12. Verify that x + y + 2 – 3xyz = 3 (x + y +z) [(x - y)2 + (y – z) + (z - x)?]
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Answer 1

Step-by-step explanation:

ANSWER

We have, L.H.S.=x3+y3+z3−3xyz

=(x+y+z)(x2+y2+z2−xy−yz−zx)           [by poynomial identity]

=21(x+y+z)(2x2+2y2+2z2−2xy−2yz−2zx)

=21[(x+y+z)(x−y)2+(y−z)2+(z−x)2]

Hence proved