Question

12% (w/v) aqueous caustic soda has a density of 1.2 g cc^-1. Calculate the mole fraction of the components. Please answer if you know it asap!!!

Answer 1

So the question says 1.00 molal aqueous solution, which means 1.00 moles of the solute is present in 1000 g of the solvent. Hence the answer is 0.017683. This can be rounded off to 0.0177. So, the correct answer is 0.0177.

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