Question

12% (w/v) aqueous caustic soda has a density of 1.2 g cc^-1. Calculate the mole fraction of the components. Don't give irrelevent answers. I ll report if there are any....

Answer 1

Answer:

HII

Explanation:

Molar mass of NaOH=40 g

Mass of NaOH=10 g

Molar mass of water = 18 g

Given mass of water = 90 g

Number of moles of NaOH=  

40

10

​  

=0.25 moles

Number of moles of H  

2

​  

O=  

18

90

​  

=5 moles

Mole fraction of NaOH=  

0.25+5

0.25

​  

=0.047