Question

12. What should be subtracted from -8y⁵+8y+28 to get 5y + 1?​

Answer 1

Answer:

Let the number be x.

$( - 8 {y}^{5} + 8y + 28) - x = 5y + 1$

$( - 8 {y}^{5} + 8y + 28) - (5y + 1) = x$

$- 8 {y}^{5} + 8y + 28 - 5y - 1 = x$

$- 8 {y}^{5} + 3y + 27 = x$

$\implies$ Hence, -8y⁵ + 3y + 27 should be subtracted from -8y⁵+ 8y + 28 to get 5y + 1.