12. What should be subtracted from
p– 6p + 7 so that it may exactly be
divisible by (p – 1)?
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Answer:
Put the value p=1 in the given equation
p 2−6p+7
p(1)⇒(1) 2−6(1)+7
p(1)⇒1−6+7=2
So, 2 should be subtracted from the given equation to make it divisible by (p-1)
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