Question

12. What will be the measure of angle of the triangle in the given circle with centre O? A B C O​

Answer 1

Step-by-step explanation:

As OA, OB and OC are radio of same circle, they are equal in length.

AO = BC & AC = OB as opp sides of parallelogram

So ACBO is a rhombus with smaller diagonal CO equal to it's sides in length.

Hence triangles AOC & BOC are equilateral.

So, angles AOC & BOC are 60°

So, <AOB = <AOC + < BOC = 60 + 60 = 120°

Answer 2

ONE ANGLE IS 60°

Step-by-step explanation:

<ABC=60°

<BCA=60°

<CAB=60°

<AOC=<COB=<AOB=120°

<OAC=<ACO=<OCB=<OBC=<OBA=<OAB=30°