12 wires of equal length and same cross section are connected in the form of a cube is the resistance of each of the wire is r then the effective resistance between the two diagonal ends would be
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Simplified circuit diagram for the given question is attached in my answer.
Lets find equalatent resistance for Part A.
Clearly, 3 resistors of resistance r are in parallel.
So Equalent resistance = r/3 (1)
For Part B,
6 resistors of resistance r are in parallel.
So equalent resistance = r/6 (2)
For part C,
3 resistors of resistance r are in parallel.
So equalent resistance = r/3. (3)
As part A, part B and part C are in series so
Equalent resistance for whole circuit will be
(1)+(2)+(3)
r/3 + r/6 +r/3
So answer comes out to be
Lets find equalatent resistance for Part A.
Clearly, 3 resistors of resistance r are in parallel.
So Equalent resistance = r/3 (1)
For Part B,
6 resistors of resistance r are in parallel.
So equalent resistance = r/6 (2)
For part C,
3 resistors of resistance r are in parallel.
So equalent resistance = r/3. (3)
As part A, part B and part C are in series so
Equalent resistance for whole circuit will be
(1)+(2)+(3)
r/3 + r/6 +r/3
So answer comes out to be
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Answered by
0
Answer:
5r/6
Explanation:
Simplified circuit diagram for the given question is attached in my answer.
Lets find equalatent resistance for Part A.
Clearly, 3 resistors of resistance r are in parallel.
So Equalent resistance = r/3 (1)
For Part B,
6 resistors of resistance r are in parallel.
So equalent resistance = r/6 (2)
For part C,
3 resistors of resistance r are in parallel.
So equalent resistance = r/3. (3)
As part A, part B and part C are in series so
Equalent resistance for whole circuit will be
(1)+(2)+(3)
r/3 + r/6 +r/3
So answer comes out to be
5r
6
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