Question

12. Write a function that takes an array of 10 integers and a number as an argument
and displays the position of the number using binary search​

Answer 1

Explanation:

def binary_serach(arr,x):

low = 0

high = len(arr)-1

mid = 0

while high>=low:

mid = (high+low)//2

if arr[mid]>x:

low = mid+1

elif arr[mid]<x:

low = mid-1

else:

return mid

else:

return -1

arr = list(eval(input("Enter array of 10")))

x = init(input("Enter no to find index"))

binary_search(arr,x)

MARK ME AS BRAINLY