Question

12. Write the largest 3-digit number and find prime factorisation .​

Answer 1

101 is the smallest 3 digit prime number since the one and only 3digit number smaller than 101 has factors 100(2,4,5,10…) 997 is the largest 3 digit prime number since other 3 digit numbers greater than 997 has factors 998(2,499…),999(3,9….).

Answer 2

Answer:

The largest three digit number is 999.

The prime factorisation of $999$ is $3$ × $3$ × $3$ × $37$.

Step-by-step explanation:

All the three digit numbers are from 100 to 999.

Among these the largest 3 - digit number is 999.

Prime factorization: The method of breaking down the number into the prime numbers Such that multiplying these prime numbers gives the original number.

Need to find the prime factorization of the largest 3 - digit number.

Consider the largest three digit number.

999

Now,

⇒ $999=3$ × $333$

⇒ $999=3$ × $3$ × $111$

⇒ $999=3$ × $3$ × $3$ × $37$

Notice that $37$ is the prime number which cannot be factored further.

Therefore, the prime factorisation of $999$ is $3$ × $3$ × $3$ × $37$.

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