Question

12(x²+7x) ²-8(x²+7x) (2x-1)-15(2x-1)²

Answer 1

Answer:

12(x²+7x) ²-8(x²+7x) (2x-1)-15(2x-1)² = (6x² + 52x - 5)(2x² +8x + 3)

Step-by-step explanation:

12(x²+7x) ²-8(x²+7x) (2x-1)-15(2x-1)²

= 12(x²+7x) ²  - 18(x²+7x) (2x-1) + 10(x²+7x) (2x-1) - 15(2x-1)²

= 6(x²+7x) (2(x²+7x) - 3(2x - 1))  + 5(2x-1) ((2(x²+7x) - 3(2x - 1))

=  6(x²+7x)  ( 2x² + 14x - 6x + 3)  + 5(2x-1)( 2x² + 14x - 6x + 3)

= (6(x²+7x)  + 5(2x-1)) ( 2x² + 14x - 6x + 3)

= (6x² + 42x + 10x - 5)(2x² +8x + 3)

= (6x² + 52x - 5)(2x² +8x + 3)

12(x²+7x) ²-8(x²+7x) (2x-1)-15(2x-1)² = (6x² + 52x - 5)(2x² +8x + 3)