Question

12. Xsquare-7x-5=0 by using quadratic equation​

Answer 1

Answer:

The answer is $\dfrac{7\pm\sqrt{69}}{2}$

Step-by-step explanation:

Given quadratic equation is

       $x^2-7x-5=0$

 Using the quadratic formula

    $\boxed{x=\dfrac{-b\pm\sqrt{b^2-4ac}}{2a}}$

Required solution is

    $x=\dfrac{-(-7)\pm\sqrt{(-7)^2-4(1)(-5)}}{2(1)}$

        $=\dfrac{7\pm\sqrt{49+20}}{2}\\\\=\dfrac{7\pm\sqrt{69}}{2}$