Question

12. यदि a2 + b2 + c2 = ab + bc + ac, तो
का मान क्या होगा?

a+C/b​

Answer 1

Answer:

Let us assume that a^2 + b^2 + c^2 - ab - bc - ac < 0

We multiply both sides by 2 and we take:

2(a^2+b^2+c^2 - ab - bc - ac) < 0 => 2a^2 + 2b^2 + 2c^2 - 2ab - 2bc - 2ac < 0 =>

(a^2 + b^2 - 2ab) + (b^2 + c^2 - 2bc) + (a^2 + c^2 - 2ac) < 0 =>

(a-b)^2 + (b-c)^2 + (a-c)^2 < 0 which cannot be true.

Therefore, a^2 + b^2 + c^2 - ab - bc - ac is always positive except if a = b = c when it is equal to zero.

Hope it helps