Question

12 years ago, a mother was twice as old as her son. their present ages are in the ratio 14:9. find their present age

Answer 1

Let the present age of the Son be - x

then,

present age of Mother will be - 2x

Now, 20 years ago, their ages wil be 20 years less., i.e

Mother - (2x-20) & Son - (x - 20)

Then, according to given condition, Mother was 10 times the age of son, so the equation becomes :-

(2x - 20) = 10(x - 20)

(2x - 20) = (10x - 200)

8x = 180

x = 180/8

x = 22.5 (This is the age if Son)

And Mother is twice as old as her son,

So, Mothers age will be - 2X

i.e., 2 * 22.5 = 45

Hence, Mother is 45 years old !!

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Answer 2

Answer:

2x+10:x+10 = 14:9

Step-by-step explanation:

2x+10/x+10=14/9

18x+90=14x+140

4x=50

x=50/4

x =25/2

present ages are

mother : 35

son : 22.5