12. You have three resisters of 9 ohms each. By
combining them what can be (a) the highest
resistance, and (b) the lowest resistance? (c) How can
you combine them to get a resistance of 12ohms?
Answers
Answer:
Explanation:
a) the highest resistance can be obtained by connecting them in a series
Rs = R1+R2+R3
= 9+9+9
= 27 ohms
b) the least resistance can be obtained by connecting them in parallel
1/Rp = 1/R1 + 1/R2 + 1/R3
= 1/9+1/9+1/9
= 3/9
Rp = 9/3 = 3
c) you cant avhieve a 12ohm resistance using 3 resistors of 9ohms
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the highest resistance will be obtained when they are connected in series I.e
R = 9 + 9 + 9
= 27 ohm
the lowest value of resistance Will be obtained when they are connected in parallel
I.e 1/R != 1/9 +1/9 + 1/9
R=3 ohm
(3) it is not possible to obtain 12 ohm from three restrictions of 9 ohm each.
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