Question

12.Zeroes of p(x) = x^2 -2x -3 are

(1 Point)

3, -1

-3, -1

1, -3

1, 3

​

Answer 1

Answer:

(a). { - 1, 3 }

Step-by-step explanation:

p(x) = x² - 2x - 3 = (x - 3)(x + 1) ⇒ $x_{1}$ = 3 , $x_{2}$ = - 1