120 g Mg was burnt in sufficient supply of air, to
give a mixture of
M and Man. The mixture is
now dissolved in HCl to form MgCl, and NH CI, if
107 grams NH,Cl is produced. Then the moles of
MgCl, formed is:
8.
(Mg +-0, MgO, 3Mg + N, β> Mg, N,)
(MgO + 2HCI β MgCl2 + H20
Mg, N, + 8HCI + 2NH, CI + 3MgCl)
(A) 3 moles
(B) 6 moles
(C)5 moles open (D) 10 moles
ESβ
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u r stupit i am not in class 11
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