120 g of ice at 0 c is mixed with 100 g of water at 80 c find tehe final temperature of the mixture
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if we use method of mixtures formula
i.e, m 1 × t1 ×s1+ m2 ×t2×s2 /m1 + m2
= 120×0 x0.5 + 100 × 80 ×1 / 120 + 100
= 0 + 8000/ 220
= 36.3 ~°C
i.e, m 1 × t1 ×s1+ m2 ×t2×s2 /m1 + m2
= 120×0 x0.5 + 100 × 80 ×1 / 120 + 100
= 0 + 8000/ 220
= 36.3 ~°C
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