120 g of urea dissoled in 5 litre . Calculate active mass of urea
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molar mass of urea = 60 gm / mol
given mass = 120 gm
water = 5 litres = 5000 ml
so molarity = (120 x 1000) / (60 x 5000)
=120000 / 300000
=0.4 moles per litre
hope you like my answer
please make me as brainliest.
given mass = 120 gm
water = 5 litres = 5000 ml
so molarity = (120 x 1000) / (60 x 5000)
=120000 / 300000
=0.4 moles per litre
hope you like my answer
please make me as brainliest.
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