Question

120 g of urea dissolve in 500 g of h2o calculate molality of solution

Answer 1

ANSWER
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➡ MOLALITY OF THE SOLUTION,
m = w / GMW × 1000 / W (g)

➡ MASS OF THE SOLUTE, w = 120 g

➡ MASS OF THE SOLVENT, W = 500 g

➡ GMW OF UREA = 60 g

➡ m = 120 / 60 × 1000 / 500

➡ m = 2 × 2

➡ m = 4 MOLES / Kg
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Answer 2

moles mass of (NH2CONH2) =

14+2+12+16+14+2=60. moles of Urea =120g/60g/mole = 2 moles. mass of water in kg=500g/1000g/kg=0.5kg . molality of the solution=2mole×1000g/kg/0.5g=4 moles/kg