120 GM magnesium was burnt in air to give a mixture of mgo and mg3n2 the mixture is now devolve hcl to form mgcl2 and nh4cl in produce the moles of mgcl2 formed is
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CHEMISTRY
120g Mg is burnt in air to give a mixture of MgO and Mg
3
N
2
. The mixture is now dissolved in HCl to form MgCl
2
and NH
4
Cl. If 107g NH
4
Cl is produced, then determine the moles of MgCl
2
formed.
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ANSWER
Number of moles of NH
4
Cl=
53.4gmol
−1
107gm
=2mol
2Mg+O
2
→2MgO 3Mg+N
2
→Mg
3
N
2
MgO+2HCl→MgCl
2
+H
2
O
MgO+2HCl→MgCl
2
+H
2
O
Mg
3
N
2
+8HCl→3MgCl
2
+2NH
4
Cl
120gMg=
24
120
=5 moles of Mg
So 2 moles of Mg gives 2 moles of MgO and 3 moles of Mg gives one mole of Mg
3
N
2
. 1 mole MgO and 1 mole Mg
3
N
2
give one mole and 3 mole MgCl
2
respectively. Again one mole Mg
3
N
2
give 2 moles of NH
4
Cl .
The moles of MgCl
2
formed= 2×1+3=5 moles
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