120 into two parts such that two third of one number one part is equal to two fifths of other parts
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let one no be x
and another be y
so x+y=120
given that2/3x=2/5y
x=3/5y.......(1)
putting value of (1) ineqn x+y120
3/5y+y=120
y=75
therefore
x=3/5(75)
x=45
please mark my answer as brainliest
and another be y
so x+y=120
given that2/3x=2/5y
x=3/5y.......(1)
putting value of (1) ineqn x+y120
3/5y+y=120
y=75
therefore
x=3/5(75)
x=45
please mark my answer as brainliest
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