Math, asked by shazaadkhan65, 9 months ago

120 persons were present at a meeting. If there were m men and 2m women, how many were children?

Answers

Answered by 4bhixv
1

Answer:

40 children..... (i guess)

Answered by anshika642008
2

Answer:

m+2m+m=120

4m=120

m=120/4

m=30

women=2m

m=30

30*2

=60  

30+60+30=120

there were 30 children at the meeting.

Step-by-step explanation:

first make them in order

m to be considered as men

whereas we can also consider it as children so one more m

so m+2m+m=120

we will add all the m that would be equal to 4m

m will be left on one side and 120 will get divided by 4

so m=30

as women is considered as 2m we will multiply 30 and 2=60

Similar questions