Question

120. While preparing a medicine the ayurvedic doctor mixed three medicines. 240
grams of first, 380 grams of second and 500 grams of third. If the cost of first two
medicines was Rs 40/kg & Rs 70/kg and the mixture was sold at Rs 50/kg, then price
of the third medicine is
(a) Rs 49.6/kg (b) Rs 39.8/kg (c) Rs 39.6/kg (d) Rs 49.8/kg

Answer 1

Answer:

c)39.6/kg

Step-by-step explanation:

240 grams cost of first one = (240×40)/1000 = 9.6 rupees

380 grams cost of second one = (380×70)/1000 = 26.6 rupees

let say third mixture cost is y rs/kg

500 grams cost of third one = (500×y)/1000 = y/2 rupees

9.6+26.6+y/2 = 36.2+y/2 = (72.4+y)/2 rupees is the total cost of new medicine

New medicine sold at 50rs/kg

total grams that can be added to new medicine = 240+380+500 = 1120 grams

1kg is equal to 50 rupees

1000 grams=====50 rupees

1120 grams ===== z rupees

z = (50×1120)/1000 = 56 rupees

(72.4 + y)/2 = 56 rupees

72.4 + y = 56×2

72.4 + y = 112

y = 112 - 72.4 = 39.6

Third mixture cost = 39.6 rs/kg