Question

1200 is invested at 8% simple interest per annum. In how much time will it double itself? ​

Answer 1

Step-by-step explanation:

$\huge\green{AnSWer}$

Let sum of money=Rs. x

Therefore amount=Rs. 2x

Interest=sum∗time∗R/100

=x∗time∗8/100

=8x∗time/100

Amount=sum+interest

2x=x+8x∗time/100

2x=100x+8x∗time/100

200x=100x+8x∗time

100x=8x∗time

time=100x.

time=12.5years.

Answer 2

$Principal = 1200$

$Rate = 8 \: \%$

$Amount = 1200+1200 = 2400$

$SI = \frac{P×R×T}{100}$

$SI = A - P$

$2400 - 1200 = 1200 \times 8 \times \frac{t}{100 }$

$1200 = 96t$

$t = \frac{1200}{96}$

$t = 12.5 \: years$