Question

1200kg of mild steel 25; of metal is cut and removed the net weight of remaining..

Answer 1

Answer:

answer

Step-by-step explanation:

Mass of the big structure, M = 50,000 kg

Inner radius of the column, r = 30 cm = 0.3 m

Outer radius of the column, R = 60 cm = 0.6 m

Young’s modulus of steel, Y=2×10 11 Pa

Total force exerted, F=Mg=50000×9.8N

Stress = Force exerted on a single column=50000× 49.8=122500N

Young’s modulus, Y= Strain Stress Strain = Y(F/A)

Where,Area, A=π(R 2 −r 2 )=π((0.6) 2 −(0.3) 2 ) Strain =122500/[π((0.6) 2 −(0.3) 2 )×2×10 11 ]=7.22×10 −7Hence, the compressional strain of each column is 7.22×10 −7 . please mark me brainlist answer

Answer 2

Step-by-step explanation:

From 120 Kg of mild steel 25% of metal is cut and removed the net weight of remaining metal?