1204=(161+2x)(136+2x)-21896
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(161+2x)(136+2x)-21896
=(21896+322x+322x+4x×4x)-21896
=644x+4x×4x=0
=let common 4x than
=x+161=0
=x=161
=(21896+322x+322x+4x×4x)-21896
=644x+4x×4x=0
=let common 4x than
=x+161=0
=x=161
Answered by
1
150.5,2.0 it is the answer i think
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