Question

1204x+4x²=12,440 Find 'x'​

Answer 1

Answer:

$4 {x}^{2} + 1204x = 12440 \\ 4 {x}^{2} + 1204x - 12440 = 0 \\ 4( {x}^{2} + 301 + 3110) = 0 \\ 4( {x}^{2} + 311x - 10x + 3110) = 0 \\ 4( x(x + 311) - 10(x + 311)) = 0 \\ 4(x + 311)(x - 10) = 0 \\ (x + 311)(x - 10) = 0 \div 4 \\ (x + 311)(x - 10) = 0 \\ \\ x = 10 \: or \: - 311$