Math, asked by Evas, 2 months ago

1204x+4x²=12,440 Find 'x'​

Answers

Answered by Madhav4244
1

Answer:

4 {x}^{2}  + 1204x = 12440 \\ 4 {x}^{2}  + 1204x  -  12440  = 0 \\ 4( {x}^{2} +  301 + 3110) = 0 \\ 4( {x}^{2}  + 311x - 10x + 3110) = 0 \\ 4( x(x + 311) - 10(x + 311)) = 0 \\ 4(x + 311)(x - 10) = 0 \\ (x + 311)(x - 10) = 0 \div 4 \\ (x + 311)(x - 10) = 0 \\  \\ x =  10 \: or \:  - 311

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