120cc of SO2 gas is diffused through a porous membrane in 40 minute. Under similar conditions, 360cc of another gas is diffused in 30 minutes. What is the molecular weight of the other gas?
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According to Graham's law of diffusion:
r1r2=√M2√M1
where
r = rate of diffusion
M = Molecular mass
r = Volume effusedtime=Vt
So,
r1r2 = √M2√M1⇒V1/t1V2/t2 = √M2√M1
⇒180/15120/20=√64√M1 (Molecular mass of SO2 = 64 g/mol)
⇒180×20/120×15 = 8/√M1 8×120×15180×20⇒√M1
On squaring both sides⇒M1 = 16
So, molecular mass of the hydrocarbon = 16 g/molecular.
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