Question

120cc of SO2 gas is diffused through a porous membrane in 40 minute. Under similar conditions, 360cc of another gas is diffused in 30 minutes. What is the molecular weight of the other gas?
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Answer 1

Answer:

According to Graham's law of diffusion:

r1r2=√M2√M1

where

r = rate of diffusion

M = Molecular mass

r = Volume effusedtime=Vt

So,

r1r2 = √M2√M1⇒V1/t1V2/t2 = √M2√M1

⇒180/15120/20=√64√M1 (Molecular mass of SO2 = 64 g/mol)

⇒180×20/120×15 = 8/√M1 8×120×15180×20⇒√M1

On squaring both sides⇒M1 = 16

So, molecular mass of the hydrocarbon = 16 g/molecular.

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